Well I checked it out last week, got hooked and spent most of the weekend earning my "level 1" badge;-)

Aside from dusting off some long-forgotten and arcane knowledge from my youth, I found it a fantastic opportunity to stretch my fundamental ruby chops. In fact, I'd recommend a few questions at Project Euler as a right-of-passage whenever you are learning a new programming language.

I've only been using ruby for a year or so, and in that time thought I had picked up a fair bit. But I was still able to amaze myself at just how many of the problems were knocked over in just 1 or 2 lines with a bit of duck punching and liberal use of blocks with Enumerables.

I'm late to the Project Euler craze, so you will already find many people posting hints for specific questions if you just google. I thought I'd share some of the "common code" I've been building up as I go through the questions.

I put a recent copy of the source up on github for anyone who is interested (MyMath.rb), but what follows a sampling of some of the more interesting pieces.

First thing you will note is that I have written all these "common" routines as extensions to some of the fundamental classes in the ruby library: Integer, Array, String.

It doesn't have to be this way, and for less trivial activities you might be right to be concerned about messing with the behaviour of the standard classes. Maybe I'm still enjoying my ruby honeymoon period, but I do get a thrill out of being able to write things like

1551.palindrome?

=> true

## Integer Extensions

It's just so easy to code up simple calculation and introspection routines..

class Integer

# @see project euler #15,20,34

def factorial

(2..self).inject(1) { |prod, n| prod * n }

end

# sum of digits in the number, expressed as a decimal

# @see project euler #16, 20

def sum_digits

self.to_s.split('').inject(0) { |memo, c| memo + c.to_i }

end

# num of digits in the number, expressed as a decimal

# @see project euler #25

def num_digits

self.to_s.length

end

# tests if all the base10 digits in the number are odd

# @see project euler #35

def all_digits_odd?

self.to_s.split('').inject(0) { |memo, s| memo + ( s.to_i%2==0 ? 1 : 0 ) } == 0

end

# generates triangle number for this integer

# http://en.wikipedia.org/wiki/Triangle_number

# @see project euler #42

def triangle

self * ( self + 1 ) / 2

end

end

Prime numbers feature heavily on Project Euler, and I think calculating a prime series was my first lesson on why you can't brute-force everything;-) Enter the Sieve of Eratosthenes and related goodness..

class Integer

# http://en.wikipedia.org/wiki/Prime_factor

# @see project euler #12

def prime_factors

primes = Array.new

d = 2

n = self

while n > 1

if n%d==0

primes << d

n/=d

else

d+=1

end

end

primes

end

# http://en.wikipedia.org/wiki/Divisor_function

# @see project euler #12

def divisor_count

primes = self.prime_factors

primes.uniq.inject(1) { |memo, p| memo * ( ( primes.find_all {|i| i == p} ).length + 1) }

end

#

# @see project euler #12, 21, 23

def divisors

d = Array.new

(1..self-1).each { |n| d << n if self % n == 0 }

d

end

# @see project euler #

def prime?

divisors.length == 1 # this is a brute force check

end

# prime series up to this limit, using Sieve of Eratosthenes method

# http://en.wikipedia.org/wiki/Sieve_of_Eratosthenes

# @see project euler #7, 10, 35

def prime_series

t = self

limit = Math.sqrt(t)

a = (2..t).to_a

n = 2

while (n < limit) do

x = n*2

begin

a[x-2]=2

x+=n

end until (x > t )

begin

n+=1

end until ( a[n-2] != 2 )

end

a.uniq!

end

# @see project euler #23

def perfect?

self == divisors.sum

end

# @see project euler #23

def deficient?

self > divisors.sum

end

# @see project euler #23

def abundant?

self < divisors.sum

end

end

Next we visit the Collatz conjecture and an interesting routine to make numbers "speak english"..

class Integer

# http://en.wikipedia.org/wiki/Collatz_conjecture

# @see project euler #14

def collatz_series

a = Array.new

a << n = self

while n > 1

if n % 2 == 0

n /= 2

else

n = 3*n + 1

end

a << n

end

a

end

# express integer as an english phrase

# @see project euler #17

def speak

case

when self <20

["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten",

"eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" ][self]

when self > 19 && self < 100

a = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"][self / 10 - 2]

r = self % 10

if r == 0

a

else

a + "-" + r.speak

end

when self > 99 && self < 1000

a = (self / 100).speak + " hundred"

r = self % 100

if r == 0

a

else

a + " and " + r.speak

end

when self > 999 && self < 10000

a = (self / 1000).speak + " thousand"

r = self % 1000

if r == 0

a

else

a + ( r <100 ? " and " : " " ) + r.speak

end

else

self

end

end

end

Calculating integer partitions is one of my favourites ... a nice, super-fast recursive algorithm. For problems like "how many ways to make $2 in change?"

class Integer

# calculates integer partitions for given number using array of elements

# http://en.wikipedia.org/wiki/Integer_partition

# @see project euler #31

def integer_partitions(pArray, p=0)

if p==pArray.length-1

1

else

self >= 0 ? (self - pArray[p]).integer_partitions(pArray ,p) + self.integer_partitions(pArray,p+1) : 0

end

end

end

Finally, rotations and palindromes (base 2 or 10): methods that rely on some underlying String routines that come later...

class Integer

# returns an array of all the base10 digit rotations of the number

# @see project euler #35

def rotations

self.to_s.rotations.collect { |s| s.to_i }

end

# @see project euler #4, 36, 91

def palindrome?(base = 10)

case base

when 2

sprintf("%0b",self).palindrome?

else

self.to_s.palindrome?

end

end

end

## Array Manipulations

Array handling is particularly important. Start with some simple helpers, then move onto greatest common factor and a couple of least-common multiple implementations. My favourite here - lexicographic permutations.

class Array

# sum elements in the array

def sum

self.inject(0) { |sum, n| sum + n }

end

# sum of squares for elements in the array

# @see project euler #6

def sum_of_squares

self.inject(0) { |sos, n| sos + n**2 }

end

# @see project euler #17

def square_of_sum

( self.inject(0) { |sum, n| sum + n } ) ** 2

end

# index of the smallest item in the array

def index_of_smallest

value, index = self.first, 0

self.each_with_index {| obj, i | value, index = obj, i if obj<value }

index

end

# removes numbers from the array that are factors of other elements in the array

# @see project euler #5

def remove_factors

a=Array.new

self.each do | x |

a << x if 0 == ( self.inject(0) { | memo, y | memo + (x!=y && y%x==0 ? 1 : 0) } )

end

a

end

# http://utilitymill.com/edit/GCF_and_LCM_Calculator

# @see project euler #5

def GCF

t_val = self[0]

for cnt in 0...self.length-1

num1 = t_val

num2 = self[cnt+1]

num1,num2=num2,num1 if num1 < num2

while num1 - num2 > 0

num3 = num1 - num2

num1 = [num2,num3].max

num2 = [num2,num3].min

end

t_val = num1

end

t_val

end

# http://utilitymill.com/edit/GCF_and_LCM_Calculator

# @see project euler #5

def LCM

a=self.remove_factors

t_val = a[0]

for cnt in 0...a.length-1

num1 = t_val

num2 = a[cnt+1]

tmp = [num1,num2].GCF

t_val = tmp * num1/tmp * num2/tmp

end

t_val

end

# brute force method:

# http://www.cut-the-knot.org/Curriculum/Arithmetic/LCM.shtml

# @see project euler #5

def lcm2

a=self.remove_factors

c=a.dup

while c.uniq.length>1

index = c.index_of_smallest

c[index]+=a[index]

end

c.first

end

# returns the kth Lexicographical permutation of the elements in the array

# http://en.wikipedia.org/wiki/Permutation#Lexicographical_order_generation

# @see project euler #24

def lexicographic_permutation(k)

k -= 1

s = self.dup

n = s.length

n_less_1_factorial = (n - 1).factorial # compute (n - 1)!

(1..n-1).each do |j|

tempj = (k / n_less_1_factorial) % (n + 1 - j)

s[j-1..j+tempj-1]=s[j+tempj-1,1]+s[j-1..j+tempj-2] unless tempj==0

n_less_1_factorial = n_less_1_factorial / (n- j)

end

s

end

# returns ordered array of all the lexicographic permutations of the elements in the array

# http://en.wikipedia.org/wiki/Permutation#Lexicographical_order_generation

# @see project euler #24

def lexicographic_permutations

a=Array.new

(1..self.length.factorial).each { |i| a << self.lexicographic_permutation(i) }

a

end

end

## String Helpers

Last but not least, some String methods that just make things so much easier...

class String

# sum of digits in the number

# @see project euler #16, 20

def sum_digits

self.split('').inject(0) { |memo, c| memo + c.to_i }

end

# product of digits in the number

# @see project euler #8

def product_digits

self.split('').inject(1) { |memo, c| memo * c.to_i }

end

#

# @see project euler #4, 36, 91

def palindrome?

self==self.reverse

end

# returns an array of all the character rotations of the string

# @see project euler #35

def rotations

s = self

rots = Array[s]

(1..s.length-1).each do |i|

s=s[1..s.length-1]+s[0,1]

rots << s

end

rots

end

end

With all the above in place - and with the aid of a few brain cells - some deceptively complicated questions (like "How many different ways can £2 be made using any number of coins?") are essentially one-liners:

require 'benchmark'

require 'MyMath'

Benchmark.bm do |r|

r.report {

answer = 200.integer_partitions([200,100,50,20,10,5,2,1])

}

end

Love it;-)