Here's a simple trick that uses the (relatively obscure) variable expansion and substring replacement capabilities of the shell.
#!/bin/bash
v_range="1..3" # or you could have taken it as a script parameter
v_start=${v_range%%.*} # chomp everything from the left-most matching "."
v_end=${v_range##*.} # chomp everything up to the right-most matching "."
The repeated %% and ## basically mean you will get a "greedy" match, so you can say "1..4" or "1....5"; it doesn't matter how many repeats you have of the range delimiter. Of course, you can choose other delimiters such as a hyphen, as in "5-10", if you wish.
Now that you have extracted the start and end indices, you can then loop or whatever to your hearts content:
for ((a=v_start; a <= v_end ; a++))
do
echo "Looping with a=$a"
done
For more information on variable expansion, see 9.3 in the Advanced Bash Scripting Guide.
Postscript 5-Feb-2008:
We live and learn! Hat tip to buford for alerting me to the seq utility, which simplifies the iteration over a range, as in:
for a in `seq 1 10`
do
echo "Looping with a=$a"
done
You still need to determine the start and end values of the range, which is the whole point of the variable expansions approach posted here.